There is a bag filled with 4 blue and 5 red marbles.
A marble is taken at random from the bag, the colour is noted and then it is not replaced.
Another marble is taken at random.
What is the probability of getting 2 of the same colour?
Answers
Step-by-step explanation:
Given :
The length of AB = 15 cm
The length of AC = 17 cm
To Find :
The length of BC
Solution :
The given triangle is an right angled triangle. So , applying pythogoreas theorem,
Square of the hypotenuse of the right angled triangle is equal to the sum of the squares of other two sides.
In the given right angled triangle ABC,
AC is the hypotenuse {Side opppsite to the right angle}
So ,
\begin{gathered} \\ : \implies \sf \: (AC)^2 = (AB)^2 + (BC)^2 \\ \\ \end{gathered}:⟹(AC)2=(AB)2+(BC)2
\begin{gathered} \\ : \implies \sf \: {(17)}^{2} = {(15)}^{2} + (BC)^2 \\ \\ \end{gathered}:⟹(17)2=(15)2+(BC)2
\begin{gathered} \\ : \implies \sf \: 289 = 225 + (BC)^2 \\ \\ \end{gathered}:⟹289=225+(BC)2
\begin{gathered} \\ : \implies \sf \: 289 - 225 =(BC)^2 \\ \\ \end{gathered}:⟹289−225=(BC)2
\begin{gathered} \\ : \implies \sf \: (BC)^2 = 64 \\ \\ \end{gathered}:⟹(BC)2=64
\begin{gathered} \\ : \implies \sf \: BC = \sqrt{64} \\ \\ \end{gathered}:⟹BC=64
\begin{gathered} \\ : \implies{\underline{\boxed{\pink {\mathfrak{BC = 8 \: cm}}}}} \: \bigstar \\ \\ \end{gathered}:⟹BC=8cm★
Hence ,
The length of the unknown side of the given right angled triangle is 8 cm.
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