Question

There is a bag with only milk and dark chocolates.
The probability of randomly choosing a dark chocolate is 3/8.

There are 21 dark chocolates in the bag and each is equally likely to be chosen.
Work out how many milk chocolates there must be.

Answer 1

Answer:

firstly

the probability of getting dark chocolate = 3/8

let the number of black chocolates be x

so,

21/x+21 = 3/8

=> 168 = 3x+63

=> 3x=105

=> x = 35

so the number of milk chocolates is 35

total number of chocolates = 21+35 = 56

probability of getting a milk chocolate=35/56 = 5/8

Step-by-step explanation:

HOPE IT HELPED YOU

Answer 2

Answer:

35 White Chocolates

Step-by-step explanation:

P (Dark Chocolate) = 3/8

P (Dark Chocolate) = 21/☐

So:

3/8 = 21/☐

  = 3x7 = 21

  = 8x7 = 56

So:

P (Dark Chocolate) = 21/56

So:

P (Milk Chocolate) = 56 - 21

  =35

So, there will be 35 milk chocolates.