Question

There is a bell at the top of a tower that is 50 m high. The bell weighs 190 Kg. Calculate the Gravitational Potential Energy of the bell

Answer 1

Answer:

Gravitational Potential Energy of the bell= mass×grav.acc×height= 50 × 190 × 9.8 = 93100kgm/s^2

Answer 2

The bell has 8550 J energy. given, There is a bell at the top of a tower

that is 45 m high. The bell weighs 190 N

i.e., bell is located at the top of tower, h = 45m

weight of the bell, F = 190N

work done by the gravitational force = F.cos 180° [ gravitational force (i.e., weight) acting

downward while body is located 45m above the ground. so, angle between force and h = 180°]

work done by the gravitational force = 190 x 45 x (-1)

= -8550 J

we know, potential energy = negative of work done

= -(-8550 J) = 8550 J