Computer Science, asked by subbaraoannavarapu, 6 months ago

There is a Bucket of water capacity of thes, which is
supposed to fill with a mug ofy mitres water
capacity. Say for example 100 and y=10 then,
bucket will get full of minimum of 8 mugs > 80% and
less than 100%
Bucket filling is to be stopped once more than 80% of
bucket capacity is filled.
The amount of water taken at a time in mug is not
fixed as it can be any value less than or equal to y.
Notify to stop once bucket is full that is more than
80% of capacity of bucket and count number of mugs
poured into bucket.
Note that Bucket capacity will always be greater that
Mug's Capacity.
Example 1:
INPUT VALUES
100
// Enter Bucket capacity in litres as this
20
1/ Enter Mug capacity in litres as this
//Enter Amount of water in MUG one after other as
below
20
20
20​

Answers

Answered by keyboardavro
0

Answer:

very long mate

Explanation:

Answered by KunalNamdev
0

import java.util.Scanner;

public class Bucket {

 

public static void check(int a,int b){

 int count=0,fill=0;double cal=0;int flag=0;

 cal = a*0.8;

 if(b>a){

  flag=1;

 }

 else{

  System.out.println("Enter your amount of water in mugs");

  while(fill<cal){

   Scanner sc = new Scanner(System.in);

   int mugs = sc.nextInt();

   if(mugs>b || mugs<0){

    flag=1;

    break;

   }

   else{

    fill+=mugs;

    count+=1;

   }

  }

   

 }

 if(flag==0){

  System.out.println("Number of mugs to fill a bucket :"+count);

 }

 else{

  System.out.println("Invalid input");

 }

}

public static void main(String[] args) {

 Scanner sc = new Scanner(System.in);

 System.out.println("Enter a Bucket Size in Lit and Size of Mug");

 int bsx =sc.nextInt();

 int msx = sc.nextInt();

 

 check(bsx,msx);

}

}

Similar questions