Question

There is a Bucket of water capacity of x litres,
which is supposed to fill with a mug ofy
millilitres water capacity. Say for example x=100
and y=10 then, bucket will get full of minimum
of 8 mugs (> 80% and less than 100%>.
Bucket filling is to be stopped once more than
80% of bucket capacity is filled.
The amount of water taken at a time in mug is
not fixed as it can be any value less than or
equal to y
Notify to stop once bucket is full that is more
than 80% of capacity of bucket and count
number of mugs poured into bucket.
Note that Bucket capacity will always be greater
that Mug's Capacity.
​

Answer 1

Answer:

okay.kkkkkkkkkkkkkkkkkk

Answer 2

Answer:

#include <stdio.h>

int main()

{

int x=0,y=0,count=0,fill=0,cal=0,temp,flag=0;

printf("enter the Bucket and Mug capacity\n");

scanf("%d %d",&x,&y);

cal=x*0.8;

if(y>x)

{

 flag=1;

}

else  

{  

 printf("Enter Amount of water in MUG one after other as below\n");

 while(fill<cal)

 {

  scanf("%d",&temp);

  if(temp>y || temp<0)

  {

   flag=1;

   break;

  }

  else

  { fill+=temp;

   count+=1;  

  }

 }

   

}

if(flag==0)

 printf("Bucket Full \nnumber of mug %d",count);

 else

 printf("Invalid input");

return 0;

}