Question

There is a bulb operating 200w - 200v find its resistance and maximum current which can pass through it without the bulb getting fused

Answer 1

P=V^2*R

200=200*200*R

200/200*200=R

0.005 ohm =R

V=I*R

200=I*0.005

200/0.005=I

I=40000 A