Math, asked by kiranmasna17, 1 month ago

There is a certain sum of money from which Anmol takes 20%, Golu takes 50% of the remaining, Yash takes Rs.1200 less than the amount taken by Golu and Shivam takes rest amount. If Anmol got Rs.400 less than Yash, then find amount taken by Golu is how much more than amount taken by Shivam. 1. Rs.2700 2. Rs.2400 3. Rs.1500 4. Rs.2000 5. Rs.1800​

Answers

Answered by spandanp2005
2

Answer:

Option 4) Rs.2000

Step-by-step explanation:

Let total money be Rs.x . Anmol took 20% i.e. Rs.x/5, so Rs.4x/5 remains.

Golu took 50% of Rs.4x/5 i.e. 2x/5, so Rs.2x/5 remains.

Yash took Rs.2x/5-1200, so Rs.1200 remains which Shivam gets.

Anmol got x/5=(2x/5-1200)-400 i.e. 400 less than Yash. Solving for x;

x/5=1600 so x=Rs.8000

Golu took 2x/5 i.e. 2*8000/5=Rs.3200

Golu - Shivam = 3200-1200 = Rs.2000

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