Question

There is a chain of length
6m
and coefficient of friction 1/2
. What will be the maximum length of chain which can be held outside the table without sliding?

please ans fast ... will mark as brainliest... any spam will be reported

Answer 1

Given:

There is a chain of length 6m and coefficient of friction 0.5 .

To find:

Maximum length of chain which can be held outside the table without sliding?

Calculation:

Lets assume that the length of chain outside the table be x metres.

So, the length of chain inside the table will be (6-x) metres.

Now, during equilibrium conditions the frictional force experienced by the chain on the table will be equal and opposite to the weight of the hanging portion.

$\rm\therefore \: f_{inside} = F_{hanging}$

$\rm \implies \: \mu \times N = mg$

$\rm \implies \: \mu \times \bigg\{A \times (6 - x) \times \rho \times g \bigg \}= \bigg \{A \times x \times \rho \bigg \}g$

$\rm \implies \: \mu (6 - x) = x$

$\rm \implies \: \dfrac{1}{2} \times (6 - x) = x$

$\rm \implies \: 6 - x = 2x$

$\rm \implies \: 3x = 6$

$\rm \implies \: x = 2 \: m$

So, length of chain outside the table (hanging part) is 2 metres.