Question

There is a circular park of radius 24 m and there is a pole at a distance of 26 m from thecentre of the park as shown in the figure. It is planned to enclose the park beplantingtrees along line segments PQ and PR tangential to the park.Paper-13​

Answer 1

Answer:

PQ + PR = 20 m

Step-by-step explanation:

There is a circular park of radius 24 m and there is a pole at a distance of 26 m from the centre of the park

PQ & PR are tangents

=> PQ = PR

PQ² =  OP² - OQ²

OP = 26 m

OQ = 24 m ( Radius)

PQ² = 26² - 24²

=> PQ² = (26 + 24)(26 - 24)

=> PQ² = 50 * 2

=> PQ² = 100

=> PQ = 10 m

   PR = 10 m

10 m + 10 m = 20 m

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