Math, asked by sumandas20160, 2 months ago

There is a clock in a kitchen. As long as there is fire in the water it goes 8.5 seconds evil and as long as the fire is not in the water it goes fast 5.1 seconds. In total 48 hours the clock shows the exact time how long the fire is in the water in 48 hours ?​

Answers

Answered by shawrkskolkata86
1

Step-by-step explanation:

answer total 18 hours hobe

Attachments:
Answered by vinod04jangid
0

Answer:

18 hours.

Step-by-step explanation:

Given :- When fire is in the water, clock is 8.5 seconds slow and when fire is not in the water, clock is 5.1 seconds fast.

To find :- Time for which fire is in the water.

Solution :-

Let the amount of time for which fire is in the water be x hours.

So, time for which the fire is not in the water = 48 - x.

It is given that, when fire is in the water, clock is 8.5 seconds slow and when fire is not in the water, clock is 5.1 seconds fast.

Acc. to the question,

8.5 × x = 5.1 × ( 48 - x )

⇒ 8.5x = 244.8 - 5.1x

⇒ 8.5x + 5.1x = 244.8

⇒ 13.6x = 244.8

⇒ x = 244.8 ÷ 13.6

⇒ x = 18 hours

Therefore, for 18 hours fire is in the water.

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