There is a coin on the bottom of a vessel.water is filled into the vessel upto a height 40cm.at what depth from the surface of water the coin appears to remain when observe normally from above.
Refraction index of water = 4/3
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2
Answer:
Real depth/Apparent depth= RI
AD= RD/RI
= 40/ (4/3)
= 40×3/4=30cm
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0
Answer:
PHYSICS
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Asked on December 27, 2019 by
Balagopal Jinka
The depth of water in a bucket is 40 cm but its bottom appears to be raised by 10 cm. What is the refractive index of water ?
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ANSWER
The real depth of water in bucket is 40 cm
The apparent depth of water in bucket is 40 - 10 = 30 cm
refractiveindex=
apparentdepth
actualdepth
refractiveindex=
d
apparent
d
actual
=
30
40
=
3
4
μ=
3
4
Explanation:
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