There is a continuous growth in population of a village at the rate of 5% per annum. If
its present population is 9261, what it was 3 years ago?
Answers
Answered by
3
Answer:
8000
Step-by-step explanation:
Let P be the population 3 years ago
Then present population = P x
(1+5/100)^3
9261=(P×21/20×21/20×21/20)
or P= (9261×20/21×20/21×20/21)
=8000
Hence, three years ago the population of the village was 8000
Answered by
7
Given:
A village with
- Present population = 9261
- Growth rate = 5%
- Time = 3 years
What To Find:
We have to find the population of the village 3 years ago.
How To Find:
To find the population of the village 3 years ago, we will use the
- Formula of amount in compound interest i.e .
- Substitute the values and solve.
Solution:
Using the formula,
⇒
Substitute the values,
⇒
Solve the brackets,
⇒
Convert the fraction into decimal,
⇒
Remove the brackets,
⇒ A = 9261 × 1.05 × 1.05 × 1.05
Multiply the numbers,
⇒ A = 8000
∴ Therefore, the population of the village three years ago was 8000.
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