Question

there is a cube whose side is 6 inch and a cuboid whose length , breath, heigth is 9inch , 6inch and 5inch respectively. which figure has larger surface area? ​

Answer 1

Answer:

cuboid

Step-by-step explanation:

because 6•6•6=216

but

6•9•5=270

Answer 2

Answer:

The cuboid has the larger surface area.

Step-by-step explanation:

The T.S.A of cube is 6a^2

T.S.A of cuboid is 2(lb+bh+lh)

the side of cube is 6inches.

the T.S.A of cube =6×(6)^2

6×36

=196sq cm

T.S.A of cuboid =2(9×6+6×5+9×5)

=2(54+30+45)

=2(130)

=260sq cm

There fore the cuboid figure has larger surface area. Hence proved//.

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