Question

there is a current of 0.50a through an incandescent lamp for 5.0 min , with a voltage of 115v. how much energy does it transfer to the lamp what is the power rating of the land

Answer 1

Explanation:

current is 2 ampere

time is 5 min which is 300 sec

charge is

Q=IT

2×300=600C

now,

P.D is 115 v

Q is 600C

work done is P.D×CHARGE

so, 115×600 = 69000 J

which is 69KJ

Answer 2

Answer:

17.25 kJ

Explanation:

P=VIt

P=115*0.5*300(sec)=17250 J