Math, asked by panwarshakila, 7 months ago

There is a defective die in which two dots instead of four are printed. In which die, the chance of getting '2' is more, in defective die or in normal die? Give the reason.

Answers

Answered by srjgaudo

Answer:

defective

Step-by-step explanation:

because in a normal dice, there is only face that has 2 on it but on the defective since there are two faces which have 2 on it, one is the face that was originally meant to be 2 and the other face which was supposed to be 4 but now since it is defective, it shows a 2, therefore the probability in normal case is 1/6 and in defective case is 2/6

Answered by anandarti99

Answer:

hopes it helpful mark me brillant please

Step-by-step explanation:

mark me brilliant

Attachments:

Previous Question

Next Question

There is a defective die in which two dots instead of four are printed. In which die, the chance of getting '2' is more, in defective die or in normal die? Give the reason.​

Answers

There is a defective die in which two dots instead of four are printed. In which die, the chance of getting '2' is more, in defective die or in normal die? Give the reason.