Question

. There is a defective die in which two dots instead of four are printed. In which
die, the chance of getting "2 is more, in defective die or in a normal die ? Give
the reason.​

Answer 1

Step-by-step explanation

In a non defective or unbiased dice the Probability of getting a odd number or a even number is 1/2

The question suggests it is a six sided defective dice with the probability of getting a odd number is 2 times getting the probability of an even number.

Hence the numbers on the dice will be

odd odd odd

even even odd

In this case the Probability of getting the odd number is 4/6 = 2/3

Probability of getting the even number is = 2/6 = 1/3

which satisfies the condition "probability of getting a odd number is 2 times getting the probability of an even number"

Now the extra odd number could be 5 or any other odd number.

i.e

1 3 5

2 4 5

OR

1 3 5

2 4 3(or any other)

hence the probability of getting a 5 in a single throw is 2/6 or 1/6

[spoiler]2/6 + 1/6 = 3/6 = 1/2[/spoiler]