Question

there is a figure in which ABCD is a rhombus and CD is an equilateral triangle on side CD if Angle B A D is 46 degree then find angle BAC and angle d a b

Answer 1

Answer:

angle BAC=1/2 angle BAD (diagonals of a rhombos bisect one another at right angles)

therefore, angle BAC=23*

Angle DAB=angle BAD=46*