There is a heap of blocks.Anil makes separate heaps of 28 blocks from them.Shilpa makes separate heaps of 32 blocks from the same heap.Nitin makes separate heaps of 42 blocks. Each of them finds that 5 blocks are left after making the separate heaps.What is the smallest possible number of blocks in the heap?
Answers
Answer:
Total Blocks = 677
Step-by-step explanation:
There is a heap of blocks.Anil makes separate heaps of 28 blocks from them.Shilpa makes separate heaps of 32 blocks from the same heap.Nitin makes separate heaps of 42 blocks. Each of them finds that 5 blocks are left after making the separate heaps.What is the smallest possible number of blocks in the heap?
28p + 5 = 32q + 5 = 42r + 5 = Total blocks
=> 28p = 32q = 42r = Total blocks - 5
Lets find out LCM of 28 , 32 & 42
28 = 2 * 2 * 7
32 = 2 * 2 * 2 * 2 * 2
42 = 2 * 3 * 7
LCM = 2 * 2 * 2 * 2 * 2 * 3 * 7 = 672
672 = total Blocks - 5
=> Total Blocks = 677
smallest possible number of blocks in the heap = 677
Step-by-step explanation:
answer is
677
28p+5= 32q+5=42r+5=total blocks
= 28p = 32q = 42r = total blocks+ 5
28= 2×2×7
32=2×2×2×2×2
42=2×3×7
l.c.m= 2×2×2×2×2×3×7=672
672 = total blocks+ 5
=total blocks = 677
= 677 ans