Math, asked by panditpramod868, 1 month ago


There is a heap of blocks. Anil makes separate heaps of 28 blocks from them. Shilpa makes
separate heaps of 32 blocks from the same heap. Nitin makes separate heaps of 42 blocks.
Each of them finds that 5 blocks are left after making the separate heaps. What is the smallest
possible number of blocks in the heap?
[Note: The required number of blocks = (LCM of 28, 32, 42) + 5.]

Answers

Answered by Muthuraman30062006
2

Answer:

677

Step-by-step explanation:

LCM of 28, 32, 42 is 672

The required number of blocks=672+5=677

Answered by jayshreechavhan8505
0

Answer:

lcm8939384839285839201039586 484758950394575849948548484875657589403021111111111111111111111111111112222222222222222222222222222223333333334455777er7ruririrheud mathsjckd djfjfjjfjfkr

Step-by-step explanation:

Maths

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