There is a hole in a ball .Consider it to be 2d. Find the probability that the hole is closer to the boundary of ball than to the centre?
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3/4
Step-by-step explanation:
There is a hole in a ball .Consider it to be 2d. Find the probability that the hole is closer to the boundary of ball than to the centre?
Consider 2d is the radius of ball then
d is the distance equal from centet and boundry then for being closer to boundry hole should be slightly greater than d
Area closer to center slightly less than pie×d^2
Area of circle =pie (2d)^2 = pie4d^2
area of region closer to boundry slightly less than =pie 3d^2
Probability slightly less than 3/4
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