Question

There is a jungle in which 99% trees are of neem and 1% trees are of chandan . An engineer said to the owner that he will not do anything with the chandan trees but he will cut the jungle in a way such that there will be 98% neem trees left in the jungle . What percent of the jungle is cut ?​

Answer 1

GivEn :-

• There is a Jungle where 99% trees are Neem. And the rest 1% is Chandan Trees.

• An Engineer is said to cut trees and also the Engineer left Chandan tree untouched

• He Cut the tree such a way that he Left 98% of trees in The Jungle.

To FinD :-

• What percentage of Tree is cut?

SoluTioN :-

It was given that the Engineer who is Asigned to do the Work has Left 98% of trees. 99% of trees where Neem and The rest 1% where Chandan.

He left The Chandan trees Untouched and left 1% of trees.

• He didn't Cut Chandan Tree and he cleared The Neem.

• In total There were 99% of Neem Trees and After Clearing It was 98%

$\boxed{ \bold{ \underline{ \red{★He \: Cleared \: 1percentage\: of \: trees \: (Exept \: Chandan}{} }{} }{} }{}$

Answer 2

Answer:

1.98% percent of the jungle is cut.

Step-by-step explanation:

Given,There is a jungle in which 99% trees are of neem and 1% trees are of chandan .

We Know, a% of b

$= \frac{a}{100} \times b$

By some examples,we can understand this concept.

Example -1:

$5\% \: of \: 50 \\ = \frac{5}{100} \times 50 \\ = \frac{5}{2} \\ = 2.5$

Example -2:

$10\% \: of \: 500 \\ = \frac{10}{100} \times 500 \\ = 10 \times 5 \\ = 50$

Let,total number of trees are x

So, number of chandan tree

$= 1\% \: of \: x \\ = \frac{1}{100} \times x \\ = \frac{x}{100}$

and number of neem trees

$= x - \frac{x}{100} \\ = \frac{99x}{100}$

It is also given that there will be 98% neem trees left in the jungle .

So, amount of cutted neem trees = (100-98)% of total neem trees = 2% of total neem trees

$= 2\% \: of \: \frac{99x}{100} \\ = \frac{2}{100} \times \frac{99x}{100} \\ = \frac{99x}{5000}$

So, number of left neem trees

$= \frac{99x}{100} - \frac{99x}{5000} \\ = \frac{49 \times 99x}{5000} \\ = \frac{4851x}{5000}$

So, total number of left trees in the jangal

$= \frac{4851x}{5000} + \frac{x}{100} \\ = \frac{4901x}{5000}$

Therefore, total number of cutted tree

$= x - \frac{4901x}{5000} \\ = \frac{99x}{5000}$

Here x means 100%

So by Unitary method, 1 means $\frac{100}{x} \%$

and $\frac{99x}{5000}$ means

$\frac{100}{x} \times \frac{99x}{5000} \\ = \frac{99}{50} \\ = 1.98\%$

Therefore 1.98% percent of the jungle is cut.

This is a problem of percentage.

Know more about percentage:

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