There is a mixture of milk and water of amount 20 liters in the ratio 3:2. 10 liters of the mixture is
removed and replaced with pure milk and the operation is repeated once more. At the end of the two
removals and replacements, what is the ratio of milk and water in the resultant mixture?
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Step-by-step explanation:
Milk = 35×20 = 12 litres
Water = 8 litres
In 10 litres of mixture.
Milk = 6 litres
Water = 4litres
On adding 10 litres of milk,
Milk => 12 - 6 +10 = 16 litres
Water => 8 - 4 = 4 litres
Again. in 10 litres ofmixture,
Milk = 45×10 = 8 litres
Water = 2 litres
On adding 10 litres of milk,
Milk =16 - 8 + 10 = 18 litres
Water = 2 litres
Therefore, Required ratio = 18 : 2 = 9 : 1
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