Question

there is a narrow rectangular plot, reserved for a mall, in indore city. the length and breadth of the plot are in the ratio 12:3 at the rate of ₹100 per meter it will cost ₹ 12,00,000 to fence the plot.​

Answer 1

Answer:

Let the length and breadth's common ratio: x in metre

∴ Length :11x and Breadth :4x

Perimeter ⇒2(l+b)

=2(11x+4x)=30x

As per the question:

Cost of fencing plot at rate of Rs.100 per meter is Rs.75000

∴100× Perimeter =75000

3000x=75000

x=25

Length =11×x=11×25=275 m

Breadth =4x,=4×25=100 m