Question

There is a narrow rectangular plot, reserved for a school in Mahuli village. The length and breadth of the plot are in the ratio of 11:4. At the rate rs.100 per metre it will cost the village panchayat rs.75000 to fence the plot. What are the dimensions of the plot?​

Answer 1

Answer:

275m & 100m

Step-by-step explanation:

There is a narrow rectangular plot, reserved for a school, in mahuli village. the length and breadth of the plot are in the ratio 11:4. 

let the common multiple be x 

the length will be 11x 

breadth = 4x 

Perimeter = 2( L + B ) 

=2(11x+4x) 

= 2*15x

=30x 

At the rate Rs 100 per meter 

30x * 100 = 3000x 

3000x= 75000 

3x=75 

x=25 

11x = 11*25 = 275m 

4x=4*25 = 100 m 

275m & 100m are the dimensions of the Plot

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Answer 2

Answer

Let the length and breadth's common ratio: x in metre

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4x

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30x

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30xAs per the question:

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30xAs per the question:Cost of fencing plot at rate of Rs.100 per meter is Rs.75000

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30xAs per the question:Cost of fencing plot at rate of Rs.100 per meter is Rs.75000∴100× Perimeter =75000

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30xAs per the question:Cost of fencing plot at rate of Rs.100 per meter is Rs.75000∴100× Perimeter =750003000x=75000

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30xAs per the question:Cost of fencing plot at rate of Rs.100 per meter is Rs.75000∴100× Perimeter =750003000x=75000x=25

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30xAs per the question:Cost of fencing plot at rate of Rs.100 per meter is Rs.75000∴100× Perimeter =750003000x=75000x=25Length =11×x=11×25=275 m

Let the length and breadth's common ratio: x in metre∴ Length :11x and Breadth :4xPerimeter ⇒2(l+b)=2(11x+4x)=30xAs per the question:Cost of fencing plot at rate of Rs.100 per meter is Rs.75000∴100× Perimeter =750003000x=75000x=25Length =11×x=11×25=275 mBreadth =4x,=4×25=100 m