Question

There is a narrow rectangular plot, reserved for a school, in Mahuli village. The length and breadth of the plot are in the ratio 11:4. At the rate ₹100 per metre it will cost the village panchayat ₹75000 to fence the plot. What are the dimensions of the plot?

Answer 1

Answer:

Dimensions of the plot.

• Length = 275 m
• Breadth = 100 m

Step-by-step explanation:

Given that:

• The length and breadth of the plot are in the ratio 11 : 4.
• At the rate ₹100 per metre it will cost the village panchayat ₹75000 to fence the plot.

To Find:

• What are the dimensions of the plot?

Formula used:

• Perimeter = Total cost/Rate
• Perimeter of the rectangle = 2(Length + Breadth)

Finding the perimeter of the plot:

⟿ Perimeter = 75000/100

⟿ Perimeter = 750

∴ Perimeter of the rectangular plot = 750 m

Let us assume:

• Length = 11x
• Breadth = 4x

Finding the dimensions of the plot:

⟿ 2(11x + 4x) = 750

⟿ 2 × 15x = 750

⟿ 30x = 750

⟿ x = 750/30

⟿ x = 25

Dimensions of the plot:

⟿ Length = 11x

⟿ Length = (11 × 25)

⟿ Length = 275 m

⟿ Breadth = 4x

⟿ Breadth = (4 × 25)

⟿ Breadth = 100 m

Answer 2

Given :-

There  is a narrow rectangular plot, reserved for a school, in Mahuli village. The length and breadth of the plot are in the ratio 11:4. At the rate ₹100 per meter it will cost the village panchayat ₹75000 to fence the plot

To Find :-

Dimension of plot

Solution :-

At first we need to find perimeter

$\sf Perimeter = \dfrac{Cost}{Rate}$

$\sf Perimeter = \dfrac{75000}{100}$

$\sf Perimeter = 750 \; M$

Now

$\sf Perimeter = 2(l+b)$

Let

the side be 11y and 4y

$\sf 750 = 2(11y+4y)$

$\sf \dfrac{750}{2} = 11y+4y$

$\sf 375 = 15y$

$\sf \dfrac{375}{15} = y$

$\sf 25 = y$

Length = 11(25) = 275 m

Breadth = 4(25) = 100 m