There is a narrow rectangular plot, reserved for a school, in Mahuli village. The length and breadth of the plot are in the ratio 11:4. At the rate ₹100 per metre it will cost the village panchayat ₹75000 to fence the plot. What are the dimensions of the plot?
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Let the length and breadth's common ratio: x in metre
∴ Length :11x and Breadth :4x
Perimeter ⇒2(l+b)
=2(11x+4x)=30x
As per the question:
Cost of fencing plot at rate of Rs.100 per meter is Rs.75000
∴100× Perimeter =75000
3000x=75000
x=25
Length =11×x=11×25=275 m
Breadth =4x,=4×25=100 m
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Given:
- The Length and Breadth of a rectangular plot are in the ratio of 11:4. & the rate of ₹100 per m it'll cost ₹75000 to fence the plot.
To find:
- The dimensions of the plot?
Solution:
❍ Let's say, that the Length and Breadth of the plot be 11x and 4x respectively.
PERIMETER:
- Fencing of the plot requires four sides of the plot. Therefore, we've to find out the perimeter of the rectangular plot.
As we know that, Perimeter is Given by sum of its all sides. i.e. (a + b + c + d). So, Let's Solve —
⠀
- Perimeter is 30x.
⠀
Now,
Cost of Fencing
- At the rate of 100 per metre, it'll cost the village to fence the rectangular plot at ₹75000.
Required Formula:
Therefore,
- Length of the plot, 11x = 11(25) = 275 meters
- Breadth of the plot, 4x = 4(25) = 100 meters
⠀
Thank you!!
@itzshivani
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