Math, asked by Neha1111111111, 1 year ago

There is a narrow rectangular plot, reserved for a school, in mahuli village. the length and breadth of plot are in ratio 11:4 .at the rs 100 per meter is will cost the village panchayat rupees 75000 of fence the plot . what are the dimensions of the plot? please answer it's urgent

Answers

Answered by Tamash
6
Hey mate....

Given cost the village panchayat rupees 75000 of fence the plot..
since in ₹100 1 m is fenced
hence in₹75000. 75000/100=750 m is fenced

{fencing process is held on perimeter}


perimeter=750m

now let's proportion ratio is x

dimensions raatio=11:4

perimeter =2* (11x + 4x). =750m

15x=750/2
or x = 375/15. =25
Dimensions of rectangular plot
hence length=11*25=275m
breadth=4*25=100m

Hope this will be right & helpful for u..
Answered by Puneet2007
0

Answer:

Length=275 m

Breadth=100 m

Step-by-step explanation:

Given :-

  1. Ratio of Length and Breadth = 11 : 4
  2. Cost of fencing = 75000

To Find:-

Dimensions of the plot.

Solution :-

Length = 11x m.

Breadth = 4x m.

  • Perimeter of rectangular plot  = 2 (Length + Breadth)
  • Perimeter of rectangular plot  = 2 (11x + 4x)
  • Perimeter of rectangular plot  = 30x m
  • Cost of fencing = Perimeter × Rate per meter
  • 75,000 = 30x × 1000
  • 75,000 = 3000x
  • 75000/3000 = x
  • 75/3=x
  • 25 = x
  • Length = 11 × 25 = 275 m
  • Breadth = 4 × 25 = 100 m
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