There is a new data-type which can take as values natural numbers between (and including) 0 and 25. How many minimum bits are required to store this data-type.
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There is a new data-type which can take as values natural numbers between (and including) 0 and 25. how many minimum bits are required to store this datatype.
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Answer:
5 bits
Explanation:
The data type takes values from 0 to 25 including 0 and 25.
So, totally there are 26 distinct numbers.
5 bits are needed to represent 26 distinct numbers.
In general the formula for number of bits to represent n distinct values is ceil(log2n)
Therefore, number of bits needed to represent 26 numbers is ceil(log226)=5
Thank you :)
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