Question

THERE IS A NUMBER HAVING TWO DIGITS THE, ONES DIGIT IS 5 MORE THAN THE TENS DIGIT AND THE SUM OF DIGITS IS 13 FIND THE NUMBER
HOPE NOONE WIL SPAM​

Answer 1

Answer:

Let the two digit number be 10x + y where y is in unit place and x is in tenth place

y = x + 5…(1)

New number on reverse becomes 10y + x

10y + x = 8 ( x + y )…(2)

Substituting y = x + 5 in (2)

10x +50 + x = 8 ( 2x +5 )

11 x+ 50 = 16x + 40

5x = 10

x = 2

y = 7

The number : 27

Step-by-step explanation:

Answer 2

Answer:

49

Step-by-step explanation:

49is the answer because 4+9=13

and ONES DIGIT IS 5 MORE THAN THE TENS DIGIT

means 4+5=9 so the answer is 49