Question

there is a number which has 7 in 1's place. The number is exactly divisible by 3 and 9

Answer 1

Answer:

yes

Step-by-step explanation:

one place 7 and tens place 2 no is 72

No is exactly divisble by 3 and 9

Answer 2

Solution :-

given that,

• unit digits is 7 .
• Divisible by 3 and 9 .
• Smaller than 50 .

So,

→ Multiples of 3 less than 50 are = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45 and 48

→ Multiples of 9 less than 50 are = 9, 18, 27, 36 and 45

now, as we can see that, multiples of 9 less than 50 are 5 only . So, check for unit digit 7 now .

As we can see that,

→ 27 = 20 + 7

• Ten's digit = 2
• Unit's digit = 7 .

therefore, we can conclude that, the required number is 27 .

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

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