Question

There is a parallel plate capacitor of capacitances 2.0muF. The voltage between the plates of parallel plate capacitor is changing at the rate of 6.0Vs^-1. What is the displacement current in the capacitor?

Answer 1

Answer:

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Explanation:

Thus, the potential difference between the plates of both capacitors is VA - VB = Vbat. We have C1 = Q1/Vbat and C2 = Q2/Vbat, where Q1 is the charge on capacitor C1, and Q2 is the charge on capacitor C2. Let C be the equivalent capacitance of the two capacitors in parallel, i.e. C = Q/Vbat, where Q = Q1 + Q2.