there is a path along the diagonal of a rectangular park and its length is 52 m find the length of wall around the park if its one side is of 48 m
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By pythagoras
L² + B² = D²
Where L is length, B is breadth and D is diagonal
Breadth given as 48
Diagonal given as 52
Therefore,
L² + 48² = 52²
L² = 52² -48²
L² = 2704 - 2304
L² = 400
L = √400
L = 20
So perimeter of this park = 2(L+B)
= 2(20 + 48)
= 2(68)
= 136
So, the perimeter of the park is 136m.
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