Question

There is a path of 2 m width running inside
along the perimeter of a park of
dimension 32 m x 24 m that has to be
cemented. If one bag of cement is required
to cement 8m2 area, then the number of
bags of cement required to construct the
cemented path is​

Answer 1

Given:

There is a path of 2 m width running inside along the perimeter of a park of

dimension 32 m x 24 m that has to be cemented.

If one bag of cement is required to cement 8 m² area

To find:

The number of bags of cement required to construct the cemented path is​?

Solution:

The dimensions of the rectangular park:

Length, L = 32 m

Breadth, B = 24 m

∴ The area of the park including the path = L × B = 32 × 24 = 768 m²

The width of the path running inside of the park = 2m

So, the dimension excluding the path:

Length = 32 - (2 × 2) = 28 m

Breadth = 24 - (2 × 2) = 20 m

∴ The area excluding the path = 28 × 20 = 560 m²

Therefore,

The area of the path is,

= [Area including the path] - [Area excluding the path]

= 768 - 560

= 208 m²

Now,

If cementing an area of 8 m² requires = 1 bag of cement

Then,

Cementing an area of 208 m² will require = $\frac{1}{8} \times 208 = \bold{26}$

Thus, the number of bags of cement required to construct the cemented path is​ → 26.

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Also View:

a rectangular park whose length is 30 m and width is 20 m. there is a path of 1 m width running inside along the perimeter of the park that has to be cemented. if 1 bag of cement is required to cement 4 sq. meter area how many bags of cement would be required to construct the cemented path?

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A rectangular -swimming pool with dimensions 30m×20m has 5m wide cemented path along its length and 8m wide path along its width find the cost of cementing the path at the rate of₹200 per m×m

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