there is a path of width 6m along the outer boundary of a rectangular crop filed of length 180 & breadth 120m. with a proper diagram find the area of the path5
Answers
Step-by-step explanation:
There is a path of width 6 m. along the outer boundary of a rectangular
crop field of length 180 m. and breadth 120 m. The area of the path is 3744 m²
Here, we need to visualize two rectangles.
One on the outer part and the other one on the inside.
The Measurements of the outer rectangle formed as a result of the boundary are given by:
Length = 180 + (6 × 2) = 192 meters
Width = 120 + (6 × 2) = 132 meters
The area of the outer rectangle = 192 × 132 = 25344 m²
The area of the inner rectangle = 180 × 120 = 21600 m²
The area of the path = the area of the boundary
= the area of the outer rectangle - the area of the inner rectangle
= 25344 - 21600 = 3744 m²
Answer:
Length= 180m
Breadth= 120m
Area= L×B
180×120m
Path wide=6m
Length=180+6=186m
Breadth=120+6=126
Area of path= L×B
= 186×126
= 23,436.