Math, asked by suresh1690, 5 months ago

There is a Pentagonal shaped parts as shown in the figure. for finding its area jyoti and Kavita divided it in two different ways

Answers

Answered by TheUntrustworthy
11
  • First way: By Jyoti’s diagram,

Formula:

Area of pentagon = Area of trapezium ABCP + Area of trapezium AEDP

  • = (½)(AP+BC)×CP+(1/2)×(ED+AP)×DP
  • = (½)(30+15)×CP+(1/2)×(15+30)×DP
  • = (½)×(30+15)×(CP+DP)
  • = (½)×45×CD
  • = (1/2)×45×15
  • =337.5 m²

Area of pentagon is 337.5 m²

  • Second way: By Kavita’s diagram,

Here, a perpendicular AM drawn to BE.

AM = 30–15 = 15 m

Area of pentagon = Area of triangle ABE+Area of square BCDE (from above figure)

  • = (½)×15×15+(15×15)
  • = 112.5+225.0
  • = 337.5 m²

Hence, total area of pentagon shaped park = 337.5 m²

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