Question

There is a pole, 6 m tall. At base is a snake hole. A peacock on top of the pole. A snake approaches the hole from a distance thrice the height of the pole. Peacock sight the snake, swoops down diagonally at the same speed that of the snake and grabs it at a distance from the hole. What is the distance?​

Answer 1

Answer:

18.97

Step-by-step explanation:

base = 3×height of pole

= 3×6

= 18

diagonal ² = pole² + base² ( by Pythagoras theorem)

x² = 6² + 18²

x² = 36+ 324

x² = 360

x = √360

x. = 18.97 ~ 19

Answer 2

snake distance = 18

let the distance be x

and speed y

therefore

y*(x^2+36)^1/2 = y* (18-x)

x^2 + 36 = 324 + x^2 - 36x

36x= 360

x= 10

distance = 10