Question

There is a prism of refractive index 1. and prism angle 2 Find the minimum deviation caused by this prism.

Answer 1

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Let δm be the angle of minimum deviation A=δm

A=δm

μ=sin(2A)sin2(A+δm)

1.5=sin(2A)sin(2A+A)

1.5=sin(2A)sin2(2A)=sin(2A)2sin2Acos2A

1.5=2cos2A

0.75=cos2A

2A=cos−1

Answer 2

There is a prism of refractive index 1.5 and prism angle is 2°.

we have to find the minimum deviation caused by this prism..

solution : for prism of angle A,

minimum deviation is given by, δ = (μ - 1)A

here μ = 1.5 , A = 2°

so, minimum deviation = (1.5 - 1) × 2° = 1°

Therefore the minimum deviation caused by this prism is 1° i.e., correct option is (1).

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