Question

there is a rectangle d a t e and its diagonal DT and a intersect at AE and the value of AE is equal to 40 and ST is equal to X + 5 find the value of x​

Answer 1

Step-by-step explanation:

I presume you are trying to say that the diagonals intersect at point s

so length of the diagonal is 40 cm

point is divides the diagonals into two equal halves

so length of St will be equal to 20 CM

hence 20 equals to X + 5 find the value of x will be 15

this is the answer please mark brainliest