Question

There is a rectangle whose length is more than its breadth by 7 and diagonal is more than the length by 1m. find the length and the breadth of the rectangle. ​

Answer 1

Answer:

7

Step-by-step explanation:

7x1=7

Answer 2

Answer:

let breadth of rectangle  be x

so length = x+7

and diagonal =  x +7+1= x+8

since diagnol divides rectangle in two right triangles

By pythagoras theorem,

diagonal^2 = length^+ breadth^2

putting values

x^2  + 64 + 16x= x^2 + 49+ 14x + x^2

or

x^2 + 14x -16x +49 - 64 = 0

x^2 -2x -15=0

x^2 - 5x +3x -15+0

x(x - 5) +3( x-5) = 0

x is not = -3 since length can't be negative

x = 5

b=5

l= 5+7= 12

d =13

Step-by-step explanation: