Question

there is a rectangular field of diameter 60 m × 40 m. a hole is made from centre of field of dimension 10 x 10 x 10 and its soil spread to rest field. how many level of field increases​

Answer 1

Answer:

Area of rectangular field = length x breadth = 60 x 50 = 3,000 m2

Now, a = 50 m, b = 45 m, c = 35 m

s = (a + b + c)/2 = (50 + 45 + 35)/2 = 130/2 = 65 m

By Heron's formula :

∴ Area of triangle = root under(√s(s - a)(s - b)(s - c))

= root under(√65(65 - 50)(65 - 45)(65 - 35) = root under(√65 x 15 x 20 x 30)

= root under (√13 x 5 x 5 x 3 x 5 x 2 x 2 x 5 x 2 x 3)

= 5 x 5 x 3 x 2 (root under(√13 x 2))

= 150√26 = 764.85 m2 ( approximately )

Hence, the remaining area

= Area of rectangle - Area of triangle

= 3,000 - 764.85 = 2,235.15 m2