Question

there is a rectangular field of length 600 m and weight 400 m there is another field of the square shape with each side being 400m find whose perimeter is more and how much

Answer 1

Here's the answer...Hope it helps u...

Answer 2

first rectangular field has length and breadth equal to 600 m and 400m

so perimter of rectangle Rp= 2*(l+b) = 2*(600+400)=2000 m

perimeter of square Sp = 4 * a

where a is side of square

s Sp = 4*400 = 1600 m

now Rp > Sp so rectangle has more perimeter

difference of exceeded parameter = Rp - Sp = 2000- 1600 = 400 m