there is a rectangular field of size 84m by 37m. Three roads, each of 4m width , pass through the field such that two roads are parallel to the length of the field and one is parallel to its breadth then find.
a) The area of the field covered by the three roads.
b) The area of the remaining field.
SOLVE IT IF YOU CAN. ALL THE BEST.
Answers
We know that width of each road is 2m.
Length of two of the roads (parallel to the breadth) = breadth = 48m.
Length of one road (parallel to the length) = length = 80m.
i] Area of two roads parallel to the breadth = 2(width * breadth)
= 2( 2*48)
= 2(96)
= 192 m. square
ii] Area of road parallel to the length = width of road * length
= 2 * 80
= 160 m. square
Now, subtract the areas common in both the roads :
We can see that the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m. square
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m. square
The area covered by the three roads is 344 m. square.
Look at the attachment.
