There is a rectangular park of length 55
m and breadth 42 m in a JNV. It has small
flower beds in the shape of Trapezium,
Square, Triangle and circle in it as shown in
the figure. The dimensions of these flower
beds are also given. Vidyalaya has planted
Variety of flowers in these flower beds to
beautify it. The figure is given below
Answers
Answer:
Please post the figure i will answer you
Answer i) :-
→ Area of ∆ = (1/2) * Base * height = (1/2) * 2 * 3.5 = 3.5 m².
→ Area of square = (side)² = (2.5)² = 6.25 m².
therefore, Square bed has more area than triangle.
Answer ii) :-
→ Area of circle = πr² = (22/7) * 2.1 * 2.1 = 22 * 0.3 * 2.1 = 13.86m².
→ Area of trapezium = (1/2)(sum of parallel sides) * height = (1/2) * (2 + 3) * 1.5 = (1/2) * 5 * 1.5 = 2.5 * 1.5 = 3.75 m².
since ,
→ 3.5 < 3.75 < 6.25 < 13.86 .
→ ∆ < trapezium < square < circle .
therefore, triangular flower bed has least area.
Answer iii) :-
→ Perimeter of vidyalaya park = 2(L + B) = 2(55 + 42) = 2 * 97 = 194 m (Ans.)
Answer iv) :-
→ Cost of planting Jasmine flower in circular flower bed = Rate / m² * Area of circular flower bed = 8 * 13.86 = Rs.110.88 (Ans.)
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