Question

There is a rectangular plot of 75.5m by 32.5m two cross roads each 3.5m wide run across in the middle of the plot one pallerell to the length and other pallerall to the breadth find the total area of the cross roads and cost of leveling the remaining portion of the plot at rs 2.50 per square m

Answer 1

Step-by-step explanation:

the length of plot=75.5m

breadth =32.5m

width of two cross roads=3.5m

total area of both cross roads =

area of first road +area of second road -area of square made by them

=(75.5×3.5)+(32.5×3.5)-(3.5 ×3.5)

=3.5 (75.5+32.5-3.5)

=32. 5 (104.5)

$365.75 {m}^{2}$

remaining area of plot= area of plot -total area of roads

=75.5×32.5-365.75

$= 2088 {m}^{2}$

cost of leveling =2088×2.50=5220 Rs

Answer 2

Answer:

1. 365.75 m and 5220 Rs

Step-by-step explanation:

simply take out the area of EFGH ,PQRS and area of square then area of EFGH +PQRS -area of square Then remaining area = area of plot - total area of plot ×₹ 2.50 cost of levelling = remaining area of plot × ₹ 2.50 answer = ₹ 5220