There is a remainder of 3 when a number is divided by 6. What will be the remainder of the square of the same number is divided by 6?
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Answer:
Step-by-step explanation:
Let the number be X
Given
X = k(6) + 3
Where k is the quotient (say)
To find X^2
Assume the value of X^2 = a(6) + b
= (k(6) + 3)^2
= (36k^2 + 54k + 9)
= (36k^2 + 54k +6 +3)
=(6k^2 + 9k + 1)(6) + 3
Comparing the two we have
a= 6k^2 + 9k +1
b = 3
Therefore the remainder will be 3
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