there is a right angle triangle whoose hypotenuse is 4 and base is root√7 find perpendicular
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Answered by
1
h square=base square +prependicular square
16=7+xsquare
16-7=x square
9=x square
3=x
Answered by
1
AB=X cm
AC=4 cm
BC=√7 cm
In a right angles triangle,
AB^2+BC^2=AC^2
AB^2=16-7
AB=3 cm
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