Question

There is a road parallel to a circular field. What is the width of the road if the difference between the inner and outer perimeter of the road is 22 meters?​

Answer 1

Step-by-step explanation:

Let r

1

and C

1

be the radius and the circumference of the inner circle.

Let r

2

and C

2

be the radius and the circumference of the outer circle.

The width of the circular path is (r

2

−r

1

) m.

Given, C

2

−C

1

=132 m

⇒2πr

2

−2πr

1

=132

⇒2π(r

2

−r

1

)=132

⇒r

2

−r

1

=

7

22

66

⇒r

2

−r

1

=21

Thus, width of the circular path is 21 m.

solution

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Answer 2

Answer:

21m is your answer

Step-by-step explanation:

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