Question

There is a slide in a park. Its side wall have been painted in green colour with a message to keep the park clean and green if the sides of the wall are 6m 11m and 15m find the area painted in green colour.​

Answer 1

Answer :-

• Area if painted wall = 20√2 cm²

Given :-

• Length of first side = 15 metres
• Length of second side = 11 metres
• Length of third side = 6 metres

To Find :-

• The area of Painted wall.

Explanation :-

As we know, by using Heron's Formulae we need semi-perimeter of triangle or triangular object.

Finding Semi-perimeter of wall

$\implies \rm \dfrac{Side \: 1 + Side \: 2 + Side \: 3}{2}$

$\implies \rm \dfrac{15 + 11 + 6}{2}$

$\implies \rm \dfrac{32}{2}$

$\boxed { \implies \rm \bold { 16 \: cm}}$

Now, Substituting the values

$\implies \rm \sqrt{s (s - a) (s - b) (s - c)}$

$\implies \rm \sqrt{16 (16 - 15) (16 - 11) (16 - 6)}$

$\implies \rm \sqrt{16 (1) (5) (10)}$

$\implies \rm \sqrt{16 \times 1 \times 5 \times 10}$

$\implies \rm \sqrt{800}$

$\underline { \boxed { \implies \rm \bold { 20 \sqrt{2} \: cm^2 }}}$

Hence, the area of painted wall is 20√2 cm²

@Agamsain

Answer 2

Given :-

• The sides of the walls are 15m, 11m and 6m.

To Find :-

• Find the area painted in color ?

Solution :-

we know that, area of a ∆ with sides as a, b and c is ,

Area = √[s*(s - a)(s - b)(s - c)] where s is semi - perimeter.

s = (a + b + c)/2 .

so,

→ s = (15 + 11 + 6)/2

→ s = 32/2 = 16 cm.

then,

→ Area of ∆ = √[16 * (16 - 15) * (16 - 11) * (16 - 6)]

→ Area = √[16 * 1 * 5 * 10]

→ Area = √(4² * 5² * 2)

→ Area = 4 * 5√2

→ Area = 20√2 m². (Ans.)

Learn more :-

In ABC, AD is angle bisector,

angle BAC = 111 and AB+BD=AC find the value of angle ACB=?

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