Question

There is a slide in a park. One of its side wall is painted red with the message ''dogs are not allowed in the park if the side of the wall are 6m ,8m, and 10mfind the cost of painting in red at the rate of rupees 10per m2

Answer 1

ATQ,

the side wall of a slide in park is painted.

we know that side walls of slides are triangular.

let the sides of the side wall be a, b and c.

given the length of the sides :-

• a = 6m

• b = 8m

• c = 10m

therefore it's semi-perimeter = (6 + 8 + 10)/2

= 24/2 = 12m

by heron's formula, we get area

$\tt = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ \tt = \sqrt{12(12 - 6)(12 - 8)(12 - 10)} \\ \\ \tt = \sqrt{12 \times 6 \times 4 \times 2}$

= √(2 × 2 × 3 × 2 × 3 × 2 × 2 × 2)

= √(2 × 2 × 2 × 2 × 2 × 2 × 3 × 3)

= 2 × 2 × 2 × 3

= 24m²

the area of the side wall which is to be painted is 24m².

hence, total cost of painting @ rupees 10 per m² = 24 × 10

= rupees 240

Answer 2

♊♊YOUR ANSWERS♍♍

✍240 Rupees

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EXPLANATION —

Sides of Triangle are 6 m, 8 m,10 m

Semiperimeter (s) =

$s = \frac{6 + 8 + 10}{2}$

s = 12 m

By Herons Formula

$area = \sqrt{s(s - a)(s - b)(s - c)}$

$area = \sqrt{12(12 - 6)(12 - 8)(12 - 10)}$

$area = \sqrt{12 \times 6 \times 4 \times 2 } = 24 {m}^{2}$

∴area = 24 m²

Now the cost of Painting

= 24 × 10 = 240 rupess

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