Question

There is a slide in a park. one of its side walls has been painted is some colour with a massage ''keep the park clean'' if the sides of the wall are 15m. 11m. and 6m find the area painted in colour​

Answer 1

Answer:

The answer is 20√2 m square .

Step-by-step explanation:

Clearly, the side wall is in the triangular form with sides a=15 m,b=6m,c=11m.

Let 2s be the perimeter of the side wall . Then,

2s=a+b+c

2s=15+6+11

s=16

Therefore,s-a=16-15=1,s-b=16-6=10 and s-c=16-11=5.

Hence, Area to be painted in colour = Area of the side wall

=√s(s-a)(s-b)(s-c)

=√16×1×10×5

=20√2 m square .

Hope your like it.

Answer 2

Answer :-

• Area if painted wall = 20√2 cm²

Given :-

• Length of first side = 15 metres
• Length of second side = 11 metres
• Length of third side = 6 metres

To Find :-

• The area of Painted wall.

Explanation :-

As we know, by using Heron's Formulae we need semi-perimeter of triangle or triangular object.

Finding Semi-perimeter of wall

$\implies \rm \dfrac{Side \: 1 + Side \: 2 + Side \: 3}{2}$

$\implies \rm \dfrac{15 + 11 + 6}{2}$

$\implies \rm \dfrac{32}{2}$

$\boxed { \implies \rm \bold { 16 \: cm}}$

Now, Substituting the values

$\implies \rm \sqrt{s (s - a) (s - b) (s - c)}$

$\implies \rm \sqrt{16 (16 - 15) (16 - 11) (16 - 6)}$

$\implies \rm \sqrt{16 (1) (5) (10)}$

$\implies \rm \sqrt{16 \times 1 \times 5 \times 10}$

$\implies \rm \sqrt{800}$

$\underline { \boxed { \implies \rm \bold { 20 \sqrt{2} \: cm^2 }}}$

Hence, the area of painted wall is 20√2 cm²

@Agamsain